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WGU Data Management – Foundations Exam Sample Questions (Q11-Q16):

NEW QUESTION # 11
Which function removes only the leading spaces from a string?

A. LEFT
B. LTRIM
C. REPLACE
D. TRIM

Answer: B

Explanation:
TheLTRIM()function in SQL removesleading spaces(spaces at the beginning of a string) while keeping spaces at the end.
Example Usage:
sql
SELECT LTRIM(' Hello World') AS TrimmedText;
Output:
bash
'Hello World'
Why Other Options Are Incorrect:
* Option B (LEFT) (Incorrect):Used for extracting a portion of a string. Example:
sql
SELECT LEFT('Hello World', 5); -- Output: 'Hello'
* Option C (TRIM) (Incorrect):Removesboth leading and trailing spaces, not just leading ones.
Example:
sql
SELECT TRIM(' Hello World '); -- Output: 'Hello World'
* Option D (REPLACE) (Incorrect):Replaces occurrences of one substring with another but doesnot specifically remove spaces.
Thus, the correct answer isLTRIM(), which removes onlyleading spaces.

NEW QUESTION # 12
Which characteristic is true for non-relational databases?

A. They are optimized for big data.
B. They support the SQL query language.
C. They are ideal for databases that require an accurate record of transactions.
D. They store data in tables, columns, and rows, similar to a spreadsheet.

Answer: A

Explanation:
Non-relational databases(also calledNoSQL databases) are designed for handlingbig dataandunstructured dataefficiently. They are optimized forhorizontal scaling, making them ideal forlarge-scale distributed systems.
* Option A (Correct):Non-relational databases areoptimized for big data, handling massive volumes of data across distributed architectures.
* Option B (Incorrect):NoSQL databases donotuse SQL as their primary query language. They often use JSON-based queries (e.g., MongoDB).
* Option C (Incorrect):Transaction-heavy applications requireACID compliance, which relational databases (SQL) handle better than NoSQL databases.
* Option D (Incorrect):NoSQL databases usedocument, key-value, graph, or column-family storage models, nottables, columns, and rowslike relational databases.

NEW QUESTION # 13
Which type of entity only exists in a logical sense?

A. Concrete entity
B. Physical entity
C. Tangible entity
D. Intangible entity

Answer: D

Explanation:
Anintangible entityis an entity that does not have a physical presence but still holds meaning in a database.
These entities representconcepts, relationships, or abstract datathat exist in a logical sense.
Example Usage in Databases:
* Customer Loyalty Status (Gold, Silver, Bronze)
* Theloyalty levelis anintangible entitysince it is derived from other data (purchase history).
* Online User Sessions
* Asession IDexistslogically in the systembut does not have a tangible presence like a product or employee.
Why Other Options Are Incorrect:
* Option A (Concrete entity) (Incorrect):No such formal term in database design.
* Option B (Tangible entity) (Incorrect):Represents somethingphysical, like anemployeeorproduct.
* Option D (Physical entity) (Incorrect):Refers todata stored on disk, like database tables or indexes.
Thus, the correct answer isIntangible entity, as it only exists in a logical sense within the database.

NEW QUESTION # 14
Where does a primary key traditionally appear in a table?

A. In the table header
B. In the first column
C. In the last visible column
D. In the top row

Answer: B

Explanation:
Bydatabase design conventions, theprimary key is usually placed in the first columnof a table to make it easy to identify and reference.
Example Usage:
sql
CREATE TABLE Employees (
EmpID INT PRIMARY KEY, -- First column (convention)
Name VARCHAR(50),
Salary DECIMAL(10,2)
);
* EmpID is placed as the first columnfor clarity and quick access.
Why Other Options Are Incorrect:
* Option A (In the table header) (Incorrect):Table headers onlydisplay column names, they do not contain values.
* Option C (In the top row) (Incorrect):Thetop row contains data, not theprimary key definition.
* Option D (In the last visible column) (Incorrect):While technically possible,placing a primary key at the endisuncommonin database design.
Thus, the correct answer isIn the first column, as this is the standard convention in relational databases.

NEW QUESTION # 15
Which clause or statement in a CREATE statement ensures a certain range of data?

A. WHERE
B. SET
C. FROM
D. CHECK

Answer: D

Explanation:
TheCHECKconstraint is used in SQL toenforce ruleson a column's values. It ensures that data inserted into a table meets specified conditions, such as range restrictions or logical rules.
Example Usage:
sql
CREATE TABLE Employees (
ID INT PRIMARY KEY,
Name VARCHAR(50),
Salary INT CHECK (Salary BETWEEN 30000 AND 150000)
);
* This constraint ensures thatsalary values fall between 30,000 and 150,000.
* If an INSERT or UPDATE statement tries to set Salary = 20000, itfailsbecause it does notmeet the CHECK condition.
Why Other Options Are Incorrect:
* Option B (FROM) (Incorrect):Used in SELECT statements, not for constraints.
* Option C (WHERE) (Incorrect):Filters rows in queries butdoes not enforce constraints.
* Option D (SET) (Incorrect):Used for updating records (UPDATE table_name SET column = value) butnot for defining constraints.
Thus,CHECK is the correct answer, as it ensures that column values remain within an expected range.

NEW QUESTION # 16
......

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